The general equation of line passing through a point (x, y) can be written as,
[tex]y=mx+b[/tex]Here, m is the slope and b is the y intercept. Th slope can be calculated as,
[tex]m=\frac{y2-y1}{x2-x1}[/tex]For two lines to be perpendicular, the slopes will be reciprocal two each other and in opposite sign.
The given lines m is,
[tex]m\rightarrow2x+3y=6\rightarrow y=-\frac{2}{3}x+2[/tex]The slope is therefore,
[tex]m\rightarrow-\frac{2}{3}[/tex]Now, the slope of the line n can be calculated as,
[tex]n\rightarrow\frac{11-8}{8-6}=\frac{3}{2}[/tex]The slope for the line p passing through the pointes (0,3) (3, 4)can be calculated as,
[tex]p\rightarrow\frac{4-3}{3-0}=\frac{1}{3}[/tex]From the calculated slopes, we can infer that the lines m and n are perpendicular to each other.