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use the Law of Cosine to solve for the missing angle in the triangle. Round to the nearest whole degree!!! I need help step by step tried to solve but want to make sure it's right

Use The Law Of Cosine To Solve For The Missing Angle In The Triangle Round To The Nearest Whole Degree I Need Help Step By Step Tried To Solve But Want To Make class=

Sagot :

To find x, we use the law of cosines

[tex]16^2=22^2+8^2-2\cdot22\cdot8\cdot\cos x[/tex]

Now, we solve for x

[tex]\begin{gathered} 256=484+64-352\cdot\cos x \\ 256=548-352\cdot\cos x \\ 256-548=-352\cdot\cos x \\ -\frac{292}{-352}=\cos x \\ x=\cos ^{-1}(\frac{292}{352}) \\ x\approx34.2 \end{gathered}[/tex]

Hence, the angle x measures 34.2°, approximately.

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