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Sagot :
Since candy costs $6 per pound, it implies that p pounds of candy costs:
[tex]\text{ \$}6\times p=\text{ \$}6p[/tex]So $6p will be spent on candy.
Since less than $44 will be spent on candy. it follows the required inequality is:
[tex]6p<44[/tex]Solve for p in the inequality:
[tex]\begin{gathered} \frac{6p}{6}<\frac{44}{6} \\ \Rightarrow p<\frac{22}{3} \\ \Rightarrow p<7\frac{1}{3} \end{gathered}[/tex]Note that the number of pounds, p should be a positive number hence, the possible number of pounds that can be bought will be non-negative:
[tex]0\le p<7\frac{1}{3}[/tex]
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