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How many molecules of water are produced when 8.93 * 10^23 molecules of oxygen are reacted with excess hydrogen gas in the reaction below?

How Many Molecules Of Water Are Produced When 893 1023 Molecules Of Oxygen Are Reacted With Excess Hydrogen Gas In The Reaction Below class=

Sagot :

Explanation:

Oxygen gas is reacted with excess hydrogen gas to produce water according to the following equation.

2 H₂ + O₂ ---> 2 H₂O

We have to find the number of molecules of water that are produced when 8.93 * 10^23 molecules of oxygen are reacted.

First we have to convert the molecules of oxygen gas into moles using Avogadro's number. We know that there are 6.022 *10^23 molecules of oxygen in 1 mol of oxygen gas.

1 mol of O₂ = 6.022 *10^23 molecules.

moles of O₂ = 8.93 * 10^23 molecules * 1 mol/(6.022 *10^23 molecules)

moles of O₂ = 1.48 mol

2 H₂ + O₂ ---> 2 H₂O

Now, if we pay attention to the coefficients of the equation, we will see that 2 moles of H₂ will react with 1 mol of O₂ to produce 2 moles of H₂O. That means that the molar ratio between O₂ and H₂O is 1 to 2. We can use that relationship to find the number of moles of H₂O that will be produced by 1.48 moles of O₂ when reacting with excess H₂.

1 mol of O₂ : 2 moles of H₂O molar ratio

moles of H₂O = 1.48 moles of O₂ * 2 moles of H₂O/(1 mol of O₂)

moles of H₂O = 2.96 moles

And finally we can convert the moles of H₂O back to molecules using Avogadro's number again.

1 mol of H₂O molecules = 6.022 * 10^23 molecules

H₂O molecules = 2.96 moles * 6.022 *10^23 molecules/(1 mol)

H₂O molecules = 1.79 * 10^24 molecules

Answer: 1.79 * 10^24 molecules

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