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Find the equation of the line that passes through (3, 2) and (9.-2).Write it in point-slope form, slope-intercept form, and standard form.Label each!

Sagot :

equation of the line that passes through (3, 2) and (9.-2)

step 1

Find the slope

m=(-2-2)/(9-3)

m=-4/6

simplify

m=-2/3

step 2

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=-2/3

(x1,y1)=(3,2)

substitute

y-2=(-2/3)(x-3) ------> equation in point slope form

step 3

Find the equation of the line in slope intercept form

y=mx+b

we have

y-2=(-2/3)(x-3)

isolate the variable y

y-2=-(2/3)x+2

y=-(2/3)x+2+2

y=-(2/3)x+4 ------> equation in slope intercept form

step 4

Find the equation in standard form

Ax+By=C

wgere

A is a positive integer

B and C are integers

we have

y=-(2/3)x+4

Multiply by 3 both sides

3y=-2x+12

rewrite

2x+3y=12 ------> equation in standard form

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