Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
[tex]\begin{gathered} \text{The base = a} \\ \text{the expoent = c} \\ \text{The result is a}^c\text{ = b} \end{gathered}[/tex]Explanation:[tex]\begin{gathered} \text{Given:} \\ \log ^{}_ab\text{ = c} \\ To\text{ be converted to expoential form} \end{gathered}[/tex]
The conversion:
[tex]\begin{gathered} \log _b(x)\text{ = y} \\ b^y\text{ = x} \end{gathered}[/tex]Applying the principle to the given logarithm equation:
[tex]\begin{gathered} In\text{ exponential form, }\log ^{}_ab\text{ = c} \\ \text{becomes:} \\ a^c\text{ = b} \end{gathered}[/tex][tex]\begin{gathered} \text{The base = a} \\ \text{the expoent = c} \\ \text{The result is a}^c\text{ = b} \end{gathered}[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.