Answered

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Rosetta averages 148 points per bowling game with a standard deviation of 14 points. Suppose Rosetta's points perbowling game are normally distributed. Let X = the number of points per bowling game. Then X ~ N(148, 14).If necessary, round to three decimal places.

Rosetta Averages 148 Points Per Bowling Game With A Standard Deviation Of 14 Points Suppose Rosettas Points Perbowling Game Are Normally Distributed Let X The N class=

Sagot :

The z-score is given by the following equation:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Where:

[tex]\begin{gathered} x=\text{observed value} \\ \mu=\operatorname{mean} \\ \sigma=s\tan adard\text{ deviation} \end{gathered}[/tex]

Replacing the values for x = 110:

[tex]z=\frac{110-148}{14}[/tex]

Solving the operations:

[tex]z=-2.71[/tex]

This means that x = 110 is -2.71 standard deviations to the left of the mean. The mean is given as 148.

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