Joseph has $620 to spend at the bicycle store → he can spend$620 or less in the store.
- Bicycle costs $440.12
-2 bicycle reflectors cost $12.86/each
-One pair of bike gloves $19.26
-Biking outfits cost $53.96/each
Let "o" be the number of outfits he can buy without exceeding his budget, the total cost of the purchase can be expressed as follows:
[tex]\begin{gathered} \text{biclycle}+2\text{reflectors}+\text{gloves}+"o"biking\text{outfits}\leq620 \\ 440.12+2\cdot12.86+19.26+53.96o\leq620 \\ 440.12+25.72+19.26+53.96o\leq620 \\ 485.10+53.96o\leq620 \end{gathered}[/tex]The inequality:
[tex]485.10+53.96o\leq620[/tex]Can be used to determine the number of outfits he can buy.
To solve it you have to proceed as follows:
-First, subtract 485.10 from both sides of the expression
[tex]\begin{gathered} 485.10-485.10+53.96o\leq620-485.10 \\ 53.96o\leq134.90 \end{gathered}[/tex]-Second, divide both sides by 53.96
[tex]\begin{gathered} \frac{53.96o}{53.96}\leq\frac{134.90}{53.96} \\ o\leq2.5 \end{gathered}[/tex]The number of outfits he can buy is less than or equal to 2.5.
Since buying half an outfit makes no sense, the answer can be rounded down, so he can buy 2 biking outfits.