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Sagot :
Answer:
132 pounds of air.
Explanation:
The ideal air-to-fuel ratio for an engine = 14.7 : 1
The number of pounds of fuel burned by the vehicle = 9 lb
Let the pounds of air drawn to achieve this ratio = x
Then, we have:
[tex]\frac{\text{Air}}{\text{Fuel}}\colon\frac{14.7}{1}=\frac{x}{9}[/tex]Next, solve the equation above for x:
[tex]\begin{gathered} x=9\times14.7 \\ x=132.3\text{ lb} \\ x\approx132\; lb \end{gathered}[/tex]To the nearest pound, the vehicle should draw 132 pounds of air.
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