[tex]\begin{gathered} A_1=56.52ft^{2} \\ A_2=139.2ft^{2} \\ TS=195.72ft^{2} \end{gathered}[/tex]
1) In this picture, we can discern a trapezoid, a triangle, and one semicircle.
2) Let's begin from top to bottom, figuring out the area of that semicircle. A semicircle is half the area of a circle, so we can write out the following formula:
[tex]A=\frac{\pi\cdot r^{2}}{2}=\frac{3.14\cdot(6)^2}{2}=56.52ft^{2}[/tex]
Note that the diameter of that semicircle is congruent to the side of the parallelogram. And the diameter is twice the radius, so the radius is 6 ft long.
As we were told, we're considering an approximation for the value of pi.
3) Now, let's move on to the parallelogram. The area of a Parallelogram is
[tex]\begin{gathered} A=b\cdot h \\ A=12\times11.6 \\ A=139.2ft^{2} \\ ---- \\ TS=139.2+56.52=195.72ft^{2} \end{gathered}[/tex]
