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need help asap NO THIS IS NOT A QUIZ , ASSESSMENT OR TEST.

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Sagot :

From the diagram, the required length of the entire tunnel is (m + n) meters

In triangle ADC,

opposite = m

hypotenuse = 340

[tex]\begin{gathered} \sin \text{58 =}\frac{m}{340} \\ m\text{ = 340 x sin58} \\ m=288.336m \end{gathered}[/tex]

In triangle BCD,

opposite = n

Hypotenuse = 193

[tex]\begin{gathered} \sin 21=\frac{n}{193} \\ n=193\sin 21 \\ n=69.165m \end{gathered}[/tex]

The length of the tunnel is

288.336m + 69.165m

=357.501m

=357.5m ( nearest tenth)

The answer is 357.5m ( nearest tenth)

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