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discriminant for x^2-4x+1=-3

Sagot :

The given equation is

[tex]x^2-4x+1=-3[/tex]

First, we have to move the term -3

[tex]\begin{gathered} x^2-4x+1+3=0 \\ x^2-4x+4=0 \end{gathered}[/tex]

Where a = 1, b = -4, and c = 4.

The discriminant formula is

[tex]D=b^2-4ac[/tex]

Replacing the values, we have

[tex]D=(-4)^2-4(1)(4)=16-16=0[/tex]The discriminant is zero.

Given that the discriminant is zero, it means the equation has a unique solution.

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