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Sagot :
Answer
[tex]\frac{8}{2(2+2)}=1[/tex]Explanation
Operation given:
[tex]\frac{8}{2(2+2)}=[/tex]0. First, we have to solve the operation inside the parenthesis based on the hierarchy of the operations:
[tex]=\frac{8}{2(4)}[/tex]2. Then, as it is a multiplication and division has the same hierarchy, it is indifferent which to do next. For example, the multiplication in the denominator:
[tex]=\frac{8}{8}[/tex]3. Finally, doing the division we get:
[tex]=1[/tex]
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