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if AB =4x+1 and AC=5x+20, find the length of BC

Sagot :

Given:

AB = 4x + 1

AC = 5x + 20

And we have:

[tex]AC=AB+BC[/tex]

Substitute the values:

[tex]5x+20=4x+1+BC[/tex]

And solve for BC:

[tex]5x+20-4x-1=4x+1+BC-4x-1[/tex]

Add like terms:

[tex]x+19=BC[/tex]

Answer: BC = x + 19