Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
ANSWER:
0.02182 μC
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 1.057 g = 0.001057 kg
Length spring (l) = 5 cm = 0.05 m
spring stretch (x) = 1.932 cm = 0.01932 m
spring stretch + beads (x1) = 0.286 cm = 0.00286 m
The first thing to calculate is the value of the spring constant k, just like this:
[tex]\begin{gathered} F=k_sx \\ \\ F=mg \\ \\ mg=k_sx \\ \\ k_s=\frac{mg}{x} \\ \\ \text{ We replacing} \\ \\ k_s=\frac{(0.001057)(9.8)}{(0.01932)} \\ \\ k_s=0.5361\text{ N/m} \end{gathered}[/tex]When the charged beads are attached in equilibrium, therefore:
[tex]\begin{gathered} \frac{k\cdot q^2}{(l+x_1)^2}=k_s\cdot x_1 \\ \\ q^2=\frac{(k_s\cdot x_1)(l+x_1)^2}{k} \\ \\ q=\sqrt{\frac{(k_sx_1)(l+x_1)^2}{k}} \\ \\ \text{ We replacing:} \\ \\ q=\sqrt{\frac{\left(0.5361\cdot0.00286\:\right)\left(0.05+0.00286\:\right)^2}{9\cdot10^9}} \\ \\ q=2.182\cdot10^{-8}C\cdot\frac{1\text{ }\mu C}{1\cdot10^{-6}\text{ }C}=0.02182\text{ }\mu C \end{gathered}[/tex]The charge of the beads is 0.02182 μC
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
