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Sagot :
Given:
The three sides of a triangle are, n, 4n + 1, and 5n - 8.
The perimeter is 93.
To find the length of each side:
The formula of the perimeter of a triangle is,
[tex]\begin{gathered} P=a+b+c \\ 93=n+4n+1+5n-8 \\ 93=10n-7 \\ 100=10n \\ n=\frac{100}{10} \\ n=10 \end{gathered}[/tex]So, the length of the sides are,
[tex]\begin{gathered} n=10 \\ 4n+1=4(10)+1\Rightarrow41 \\ 5n-8=5(10)-8\Rightarrow42 \end{gathered}[/tex]Therefore, the length of the sides of a triangle are 10, 41, and 42.
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