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chemical A freezes at 13° lower than chemical B. if chemical A freezes at -36° C, at what temperature does chemical B freeze? Let B =B's freezing temperature.

Sagot :

ANSWER:

-23 ° C

STEP-BY-STEP EXPLANATION:

With the data of the statements we can propose the following equation

[tex]-13=A-B[/tex]

We replace by A and solve for B:

[tex]\begin{gathered} -13=-36-B \\ B=-36+13 \\ B=-23 \end{gathered}[/tex]

Chemical B freezes at -23 ° C