Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer
38.8 mL
Explanation
Given:
Molarity of KOH, Cb = 0.623 M
Volume of H2SO4, Va = 23.5 mL = 0.0235 L
Molarity of H2SO4, Ca = 0.514 M
What to find:
The volume of KOH required to neutralize the acid.
Step-by-step Solution:
Step 1: Balance the equation for the reaction.
The balanced equation for the reaction is:
[tex]H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O[/tex]Step 2: Calculate the volume of the base, KOH.
The volume of KOH can be determine using:
[tex]\frac{C_aV_a}{n_a}=\frac{C_bV_b}{n_b}[/tex]From the balanced equation, na = 1 and nb = 2. so putting the values of the given parameters into the above formula, we have:
[tex]\begin{gathered} \frac{0.514M\times0.0235L}{1}=\frac{0.623M\times V_b}{2} \\ \\ V_b\times0.3115M=0.012079M.L \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }0.3115M \\ \\ V_b=\frac{0.012079M.L}{0.3115M} \\ \\ V_b=0.0388\text{ }L \\ \\ The\text{ }volume\text{ }in\text{ }mL\text{ }is \\ V_b=0.0388\times1000mL=38.8\text{ }mL \end{gathered}[/tex]Therefore, the volume of 0.623 M KOH is required to neutralize 23.5 mL if a 0.514 M H2SO4 solution = 38.8 mL
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
