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Sagot :
let
a = height of Tv
b = width
c = diagonal
The diagonal of the Tv is 36 inches. Therefore we can use pythagoras theorem to find side a and b in other to get the area of the Tv.
[tex]\begin{gathered} a^2+b^2=c^2 \\ \frac{b}{a}=\frac{4}{3} \\ 4a=3b \\ a=\frac{3b}{4} \\ (\frac{3b}{4})^2+b^2=36^2 \\ square\text{ root both sides} \\ \frac{3b}{4}+b=36 \\ \frac{3b+4b}{4}=36 \\ \frac{7b}{4}=36 \\ 7b=144 \\ b=\frac{144}{7} \\ b=20.5714285714 \\ a^2+b^2=c^2 \\ c^2-b^2=a^2 \\ 36^2-20.5714285714^2=a^2 \\ 1296-423.1249=a^2 \\ 872.876=a^2 \\ a=\sqrt{872.876} \\ a=29.5444749488 \end{gathered}[/tex][tex]\begin{gathered} \text{area}=\text{ }29.5444749488\times20.57=607.729849697 \\ \text{area }\approx607.73unit^2 \end{gathered}[/tex]
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