Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
for c:
[tex]\begin{gathered} c^2=a^2+b^2-2ab\cos C \\ c^2=4^2+5^2-2(4)(5)\cos 100 \\ c^2=16+25-40\cos 100 \\ c^2=41-40\cos 100 \\ c^2=47.945 \\ c=\sqrt[]{47.945} \\ c=6.92 \end{gathered}[/tex]for A:
[tex]\begin{gathered} \frac{c}{\sin C}=\frac{a}{\sin A} \\ \sin A=\frac{a\times\sin C}{c} \\ \sin A=\frac{4\times\sin 100}{6.92} \\ A=\sin ^{-1}\frac{4\times\sin 100}{6.92} \\ A=34.7 \end{gathered}[/tex]for B:
[tex]180-100-34.7=45.3[/tex]answer: D
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
