We will start solving as follows:
*First: We write the equations described in the problem, those are:
Monday:
[tex]6d+2c=5.20[/tex]
Tuesday:
[tex]4d+5c=6.95[/tex]
*Seciond: We operate the expressions in order to eliminate one of the variables and solve for only one of them, that is:
5 (6d + 2c = 5.20)
-2 (4d + 5c = 6.95)
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30d + 10c = 26
-8d - 10c = -13.9
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22d = 12.1 => d = 0.55
Now, we have the price for each donut is $0.55. So, in order to determine now the value of the coffee we input this value in one of the original equations and solve for c, that is:
[tex]4(0.55)+5c=6.95\Rightarrow2.2+5c=6.95[/tex][tex]\Rightarrow5c=4.75\Rightarrow c=0.95[/tex]
So, the value for each coffee is $0.95.