Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Calculate the electric potential energy on the center of the square of the arrangement described as follows: Four charges are placed at the corners of a 11.36 cm square. The particles are as follows: 10.46 microC at x =0, y = 0, -11.34 microC at x = 11.36, y = 0, -16.6 microC at x = 11.36, y = 11.36, and 14.95 microC at x=0 and y = 11.36.

Sagot :

Our arrange looks like the following:

The potential energy in each individual point is given by:

[tex]E_p=k\frac{Q}{d}[/tex]

As all points have the same distance from the center of the square, we can calculate a single distance. We'll need the pythagorean theorem in order to calculate the distance. It can be written as the following

[tex]c^2=a^2+b^2[/tex]

Then we can calculate this using half the side of the square. We get

[tex]c^2=5.68^2+5.68^2[/tex]

By isolating c we can find

[tex]c=\sqrt[2]{5.68^2+5.68^2}=8.03cm[/tex]

This is the distance from each vertex to the center

We also need to take into account the fact that the total potential energy is the sum of potential energies

[tex]E_p=E_A+E_B+E_C+E_D[/tex]

It can then be written as

[tex]E_p=k(\frac{q_1}{d}+\frac{q_2}{d}+\frac{q_3}{d}+\frac{q_4}{d})[/tex]

Which, once we plug our values in, yields:

[tex]E=(9*10^9)(\frac{(10.46-11.34-16.6+14.95)*10^{-6}}{8.03*10^{-2}})=-283561.6438J[/tex]

Thus, our final answer is 283561.6438J

View image IsharaJ56424