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determine whether each ordered pair is a solution to the inequality (2, 10), (-5, -4), (-5, -8), (0, 4) (-8, -2)

Determine Whether Each Ordered Pair Is A Solution To The Inequality 2 10 5 4 5 8 0 4 8 2 class=

Sagot :

Solution of an inequality

In order to find if an ordered pair is a solution of

x + y > 3

we just need to add x + y using x and y values of the given ordered pairs. Then, we analyze if x + y is bigger or lower than 3

Remember that an ordered pair is given by (x, y). Then we just add the given numbers

(2, 10)

x + y = 2 + 10 = 12

(-5, -4)

x + y = - 5 - 4 = -9

(-5, -8)

x + y = -5 - 8 = -13

(0, 4)

x + y = 0 + 4 = 4

(-8, -2)

x + y = - 8 - 2 = - 10

The correct ordered pairs will be those whose result is > 3 (this mean the numbers bigger than 3). We just have two (0, 4) result is 4 and (2, 10) was 12, then

Answer: the ordered pairs that are solutions of x + y > 3 are

(0, 4) and (2, 10)

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