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Sagot :
Answer:
g(1) = 1
Explanation:
Given the piecewise function:
[tex]g(x)=\mleft\{\begin{aligned}-343x,\text{ x=-2} \\ (x-1)(x+2),\text{ x= -1} \\ x^3-x^2+1,\text{ x}\ne-2,\text{ -1}\end{aligned}\mright.[/tex]To find the value of g(1), this means x = 1
Looking at the piecewise function, the only function that satisfies the condition x = 1
is
[tex]x^3-x^2+1[/tex]Because it is for all x different from -2 and -1, and x = 1 is.
Substituting x = 1 in
[tex]x^3-x^2+1[/tex]we have:
[tex]\begin{gathered} 1^3-1^2+1 \\ \\ =1-1+1 \\ \\ =1 \end{gathered}[/tex]Therefore, g(1) = 1
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