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Sagot :
Explanation:
A chemist has 4.43 g of lithium carbonate and must prepare a 0.0600 mol/L (or 0.0600 M) solution. We have to find the volume of solution that can be made.
The molarity of a solution is defined like:
molarity = moles of solute/volume of solution in L
We already know the concentration of the solution (it is 0.0600 mol/L) and the volume is our unknown.
volume of solution in L = ?
molarity = 0.0600 mol/L
We still have to convert the mass of lithium carbonate into moles. To do that we will use the molar mass of the compound.
lithium carbonate = Li₂CO₃
mass of Li₂CO₃ = 4.43 g
molar mass of Li₂CO₃ = 73.89 g/mol
moles of Li₂CO₃ = 4.43 g * 1 mol/(73.89 g)
moles of Li₂CO₃ = 0.0600 moles
Finally we can replace the values in the formula and solve it for the volume of solution.
molarity = moles of solute/volume of solution in L
volume of solution in L = moles of solute/molarity
volume of solution in L = 0.0600 mol/(0.0600 mol/L)
volume of solution in L = 1.00 L
Answer: b) 1.00 L
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