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Sagot :
[tex]\begin{gathered} \text{POINT (2,-2)} \\ Perpendicula\text{ to the line y=}\frac{2}{5}x+2 \\ \text{FIND SLOPE-INTERCEPT EQUATION} \\ \text{Two lines are perpendicular when slope1}\cdot slope2=\text{ -1} \\ \text{slope1}\cdot slope2=\text{ -1} \\ (\frac{2}{5})\cdot slope\text{ 2=-1} \\ \text{slope 2=-1 }\cdot(\frac{5}{2}) \\ \text{slope 2 =-}\frac{5}{2} \\ y=\text{-}\frac{5}{2}x+b \\ U\sin g\text{ the point (2,-2)} \\ -2=\text{-}\frac{5}{2}\cdot(2)+b \\ -2=-5+b \\ b=-2+5 \\ b=3 \\ y=\text{-}\frac{5}{2}x+3 \\ \\ \text{The slope-intercept is }y=\text{-}\frac{5}{2}x+3 \end{gathered}[/tex]
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