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solve for x for an exponential equation of 5^(x-2) + 5^(x+1) = 126

Solve For X For An Exponential Equation Of 5x2 5x1 126 class=

Sagot :

The expression is given as

[tex]5^{x-2}+5^{x+1}=126[/tex]

Solve for x.

[tex]\frac{5^x}{5^2}+5^x\times5=126[/tex][tex]5^x(\frac{1}{25}+5)=126[/tex][tex]5^x(\frac{1+125}{25})=126[/tex][tex]5^x\times\frac{126}{25}=126[/tex][tex]5^x=25[/tex][tex]5^x=5^2[/tex]

Compare the power and find the value of x.

[tex]x=2[/tex]

Hence the value of x is 2.

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