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Last year, Pinwheel Industries introduced a new toy. It cost $ 9300 to develop the toy and $ 30 to manufacture each toy. Fill in the blanks below as appropriate.

Last Year Pinwheel Industries Introduced A New Toy It Cost 9300 To Develop The Toy And 30 To Manufacture Each Toy Fill In The Blanks Below As Appropriate class=

Sagot :

Given data:

Cost of develop: $9300

Cost of factory each toy: $30

n is the number of toys

[tex]C=mn+b[/tex]

m is the cost of factory each toy

b is the cost of develop

A)

[tex]C=30n+9300[/tex]

B) find C when n=1900

[tex]\begin{gathered} C=30(1900)+9300 \\ C=66300 \end{gathered}[/tex]

The total cost to produce n=1900 toys is $66300

C) find n when C=42300

[tex]\begin{gathered} 42300=30n+9300 \\ Subtract\text{ 9300 in both sides of the equation:} \\ 42300-9300=30n+9300-9300 \\ 33000=30n \\ \\ \text{Divide both sides of the equation into 30:} \\ \frac{33000}{300}=\frac{30}{30}n \\ \\ 1100=n \\ \\ \\ \\ \\ n=1100 \end{gathered}[/tex]

With $42300, a total of 1100 toys can

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