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Sagot :
Answer:
distance = 9.42 x 10^11 m
Acceleration = 5.94 x 10^-3 m/s2
Force = 3.56 x 10^22 N
Explanation:
Part a)
The distance travel by the earth in 1 year can be calculated as the circumference of a circle of radio r, so:
[tex]\begin{gathered} d=2\pi r \\ d=2(3.14)(1.5\times10^{11}m) \\ d=9.42\times10^{11}m \end{gathered}[/tex]So, the distance is 9.42 x 10^11 m
Part b)
The centripetal acceleration can be calculated as:
[tex]a_c=\frac{v^2}{r}[/tex]Where v is the velocity and r is the radius of the earth. So, the velocity is equal to:
[tex]v_{}=\frac{\text{distance}}{\text{time}}=\frac{9.42\times10^{11}m}{365.25\text{days x 24 hr x 60 min x 60 s}}=29850.18\text{ m/s}[/tex]Therefore, the centripetal acceleration is:
[tex]a_c=\frac{(29850.18)^2}{1.5\times10^{11}}=5.94\times10^{-3}m/s^2[/tex]Part c)
Finally, the average force that the sun exerts on the earth can be calculated by the second law of Newton as:
[tex]\begin{gathered} F=m\cdot a_c \\ F=(6\times10^{24})\cdot(5.94\times10^{-3}) \\ F=3.56\times10^{22}\text{ N} \end{gathered}[/tex]Therefore, the answers are:
distance = 9.42 x 10^11 m
Acceleration = 5.94 x 10^-3 m/s2
Force = 3.56 x 10^22 N
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