In order to find the zeros of this quadratic function, we can use the quadratic formula:
[tex]\begin{gathered} x_1=\frac{-b+\sqrt[]{b^2-4ac}}{2a} \\ x_2=\frac{-b-\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]
Using the given values of a = 3, b = 16 and c = -12, we have:
[tex]\begin{gathered} x_1=\frac{-16+\sqrt[]{256+144}}{2\cdot3}=\frac{-16+20}{6}=\frac{2}{3} \\ x_2=\frac{-16-20}{6}=-6 \end{gathered}[/tex]
So the values of x that make this equation be equal zero are x = 2/3 and x = -6.
