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What is the slope of a line perpendicular to the line whose equation is 4x-2y=-16 Fully simplify your answer.

Sagot :

Two lines are perpendicular if the multiplication of their slopes is equal to -1.

Isolating y from the equation:

[tex]\begin{gathered} 4x-2y=-16 \\ 4x-2y+16=0 \\ 4x+16=2y \\ \frac{4x+16}{2}=y \\ \frac{4x}{2}+\frac{16}{2}=y \\ 2x+8=y \end{gathered}[/tex]

The slope of this line is 2. Therefore, the slope of the line perpendicular to this one will be:

[tex]\begin{gathered} m\cdot2=-1 \\ m=-\frac{1}{2} \end{gathered}[/tex]

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