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A rectangular shaped farm whose dimensions are 20 by 40 yards. We need to use 88 yards of fencing to enclose it, so we will reduce the length and width by 2x yards. Find the dimensions of the farm.

Sagot :

Original dimensions of the rectangular farm:

Width = 20 yards

Length = 40 yards.

If we were to enclose the original farm, we would need:

P = 2*20 + 2*40

P = 40 + 80 = 120 yards of fencing.

Note we have just calculated the perimeter of the rectangle, whose formula is:

P = 2W + 2L

We only have 88 yards of fencing available, so we need to reduce the length and the width by 2x yards, thus:

New Width = 20 - 2x

New Length = 40 - 2x

New perimeter:

P = 2(20 - 2x) + 2(40 - 2x)

Operating:

P = 40 - 4x + 80 - 4x

P = 120 - 8x

This is the length of the fencing, thus:

120 - 8x = 88

Subtracting 120:

-8x = 88 - 120

-8x = -32

Dividing by -8:

x = 4

The new dimensions of the farm are:

W = 20 - 2*4 = 12 yards

L = 40 - 2*4 = 32 yards

The dimensions of the farm are 12 x 32 yards