At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Original dimensions of the rectangular farm:
Width = 20 yards
Length = 40 yards.
If we were to enclose the original farm, we would need:
P = 2*20 + 2*40
P = 40 + 80 = 120 yards of fencing.
Note we have just calculated the perimeter of the rectangle, whose formula is:
P = 2W + 2L
We only have 88 yards of fencing available, so we need to reduce the length and the width by 2x yards, thus:
New Width = 20 - 2x
New Length = 40 - 2x
New perimeter:
P = 2(20 - 2x) + 2(40 - 2x)
Operating:
P = 40 - 4x + 80 - 4x
P = 120 - 8x
This is the length of the fencing, thus:
120 - 8x = 88
Subtracting 120:
-8x = 88 - 120
-8x = -32
Dividing by -8:
x = 4
The new dimensions of the farm are:
W = 20 - 2*4 = 12 yards
L = 40 - 2*4 = 32 yards
The dimensions of the farm are 12 x 32 yards
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
