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In an aqueous solution at 25°C, if [H3O+] = 3.9 × 10⁻4 M, then [OH-] is:

Sagot :

Answer

[OH⁻] = 2.6 x 10⁻¹¹ M

Explanation

Given that:

[H₃O⁺] = 3.9 x 10⁻⁴ M

What to find:

[OH⁻]

Step-by-step solution:

For any aqueous solution, the product of [H₃O⁺] and [OH⁻] is given by:

[HO⁺] x [OH⁻] = 1.0 x 10⁻¹⁴

If one increases, the other decreases.

Putting [H₃O⁺] = 3.9 x 10⁻⁴ M into the formula above, we have:

[tex]\begin{gathered} 3.9\times10⁴\times\left[OH⁻\right]=1.0\times10⁻¹⁴ \\ \\ \left[OH⁻\right]=\frac{1.0\times10⁻¹⁴}{3.9\times10⁻⁴} \\ \\ \left[OH⁻\right]=2.6\times10^{-11}\text{ }M \end{gathered}[/tex]

Hence, [OH⁻] = 2.6 x 10⁻¹¹ M