Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

please help with the question on the screen ( 41)

Please Help With The Question On The Screen 41 class=

Sagot :

The half life of a nuclear element tells us the time it takes for a radioative material to reduce to half its value.

If the Initial amount is A_0,

then after 1 half life, remaining = 1/2 A_0

then after 2 half life, remaining = (1/2) 1/2 A_0 = 1/4 A_0

...

The half life equation is

[tex]A_t=A_0(\frac{1}{2^n}^{})[/tex]

A_0 is initial amount

n is the number of half lives that pass in interval "t"

A_t is the undecayed amount after time interval "t"

a)

Given half life is 138 days and

138 * 6 = 828 days

So,

6 half lives occur in 828 days

b)

The amount of Polonium in the sample is >>>>

[tex]\begin{gathered} A_t=A_0(\frac{1}{2^n}^{}) \\ A_t=60(\frac{1}{2^6}) \\ A_t=0.9375 \end{gathered}[/tex]

Rounded, that 0.94 grams

Correct Answer

A