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The value of f=g 4 is When g-f =1 the value of x is

The Value Of Fg 4 Is When Gf 1 The Value Of X Is class=

Sagot :

Okay, here we have this:

Let's find (f ∘ g)(4):

(f ∘g)(4)=f(g(4))=f(2)

(f ∘g)(4)=4

Now, let's calculate the value of x when (g∘f)(x)=1:

Considering that (g∘f)(x)=g(f(x))

We can see in the graph that g(x) is equal to 1 in x=1, this mean that:

f(x)=1

Now, of we see in the table we can see that f(x)=1 in x=0.

Therefore finally we obtain that the value of x when (g∘f)(x)=1 is x=0.

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