Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

You're standing on a ramp that is inclined at a 25 degree angle. The weight (Fg) experienced is 50N. What is the parallel force (Fx) and the perpendicular force (Fy)?

Youre Standing On A Ramp That Is Inclined At A 25 Degree Angle The Weight Fg Experienced Is 50N What Is The Parallel Force Fx And The Perpendicular Force Fy class=

Sagot :

The parallel component of force acting on person is,

[tex]F_x=F_g\sin \theta[/tex]

Substitute the known values,

[tex]\begin{gathered} F_x=(50\text{ N)s}in25 \\ =(50\text{ N)(}0.423) \\ \approx21.15\text{ N} \end{gathered}[/tex]

The perpendicular component of force acting on person is,

[tex]F_y=F_g\cos \theta[/tex]

Substitute the known values,

[tex]\begin{gathered} F_y=(50\text{ N)}\cos 25 \\ =(50\text{ N)(}0.906) \\ \approx45.3\text{ N} \end{gathered}[/tex]

Thus, the parallel force acting on person is 21.15 N and the perpendicular force is 45.3 N.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.