Answered

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A dog escapes his backyard and he walks 15 m south and then 7 m east before stopping what was his displacement?

Sagot :

Given:

Distance walked = 15 m south

Then the dg now walked 7 m east before stopping.

Let's find the displacement.

The figure below represents this situation:

The displacement can be said to be the shortest distance from the final position to the ending position.

To find the displacement here, apply Pythagorean theorem:

[tex]d=\sqrt[]{a^2+b^2}[/tex]

Where:

a = 15 m

b = 7 m

Thus, we have:

[tex]\begin{gathered} d=\sqrt[]{15^2+7^2} \\ \\ d=\sqrt[]{225+49} \\ \\ d=\sqrt[]{274} \\ \\ d=16.55\text{ m} \end{gathered}[/tex]

Therefore, the displacement is 16.55 m.

ANSWER:

16.55 m

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