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what is the y-intercept of the function y=-1/2 cos (3x/2)

Sagot :

we have the following:

[tex]\begin{gathered} y=-\frac{1}{2}\cos (\frac{3}{2}x) \\ x=0 \\ y=-\frac{1}{2}\cos (\frac{3}{2}\cdot0) \\ y=-\frac{1}{2}\cos (0)=-\frac{1}{2}\cdot1 \\ y=-\frac{1}{2} \\ (0,-\frac{1}{2}) \end{gathered}[/tex]

therefore, the y-intercept is (0, -1/2)

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