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Sagot :
Question 2
Answer
H2PO4- is a hydrogen-ion donor (acid) and HPO42- is a hydrogen-ion acceptor (base).
Explanation
Given the equation:
[tex]H_2PO_{4(aq)}^-\text{ }\leftrightarrows\text{ H}_{(aq)}^+\text{ + HPO}_{4(aq)}^{2-}[/tex]Required: Which ion plays the role of hydrogen-ion donor (acid) and which ion plays the role of hydrogen-ion acceptor (base) in PBS?
Solution:
H2PO4- is a hydrogen-ion donor (acid) and HPO4^2- is a hydrogen-ion acceptor (base).
In the equation above, the H2PO4- serves as a hydrogen donor, what happens is that Na2HPO4 dissociates into Na+ and HPO4-, this then results in a molecule being a proton acceptor. Where as in PBS solution, KH2PO4 dissociates into K+ and H2PO4-, this is a proton donor.
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