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How can transformation below be written algebraically

Sagot :

Given:

Vertices of ABCD:

A(-8,-4), B(8, 4), C(6, 4), D(-6, 4)

Vertices of A'B'C'D':

A'(-4, -2), B'(4, 2), C'(3, 2), D'(-3, 2)

The figure ABCD was dilated to produce figure A'B'C'D'

To find the scale factor, divide a coordinate of the the dilated figure by that of the original figure.

thus, we have:

[tex]\frac{A^{\prime}}{A^{}}=\frac{-4}{-8},\frac{-2}{-4}=\frac{1}{2},\frac{1}{2}[/tex]

Therefore, the algebraic representation of the transformation is:

[tex](\frac{1}{2}x,\frac{1}{2}y)[/tex]

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