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17. In the diagram below, DE, DF, and EF are midsegments of AABC. K b P с The perimeter of quadrilateral ADEF is equlvalent to A. AB + BC + AC AB + = AC C. 2AB + 2AC D. AB + AC

17 In The Diagram Below DE DF And EF Are Midsegments Of AABC K B P С The Perimeter Of Quadrilateral ADEF Is Equlvalent To A AB BC AC AB AC C 2AB 2AC D AB AC class=

Sagot :

we are asked to determine the perimeter of quadrilateral ADEF. The perimeter is the sum of the sides of a figure, therefore, the perimeter "P" is:

[tex]P=AD+DE+EF+FA[/tex]

Now, we have that DE = FA and AD = EF, therefore:

[tex]P=2AD+2DE[/tex]

Since triangle DEF is midsegments of triangle ABC we have 2AD = AB and 2DE = AC, therefore:

[tex]P=AB+AC[/tex]

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