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Sagot :
Numerical Evaluation of Functions
We are given the height h as a function of time t.
h(t)=250+20t
We will evaluate the function for the times provided in the table, that is:
For t=0:
h(0)=250+20(0)
h(0)=250+0=250 feet
For t=1:
h(1)=250+20(1)
h(1)=250+20=270 feet
For t=1.5:
h(1.5)=250+20(1.5)
h(1.5)=250+30=280 feet
For t=2:
h(2)=250+20(2)
h(2)=250+40=290 feet
For t=3:
h(3)=250+20(3)
h(3)=250+60=310 feet
For t=4:
h(4)=250+20(4)
h(4)=250+80=330 feet
For t=5:
h(5)=250+20(5)
h(5)=250+100=350 feet
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