Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
The initial expression is:
[tex]\int (t-5)^3\text{ dt}[/tex]First we can expant cube so:
[tex]\int t^3-15t^2+75t-125[/tex]and now we can integrate so:
[tex]\frac{t^4}{4}-5t^3+\frac{75t^2}{2}-125t+C[/tex]So is option B
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
