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Find the value of x in the givenright triangle.12x = [?]62°хEnter your answer as a decimal rounded to thenearest tenth.

Find The Value Of X In The Givenright Triangle12x 62хEnter Your Answer As A Decimal Rounded To Thenearest Tenth class=

Sagot :

Given:

Angle =62 degrees.

Adjacent side=x and Hypotenuse=12.

Consider the cosine formula

[tex]\cos \theta=\frac{Adjacent\text{ side}}{\text{Hypotenuse}}[/tex]

Substitute Angle =62 degrees, Adjacent side=xm and Hypotenuse=12, we get

[tex]\cos 62^o=\frac{x}{12}[/tex]

[tex]12\times\cos 62^o=x[/tex]

[tex]12\times0.4695=x[/tex][tex]x=5.6[/tex]

Hence the value of x is 5.6 units.

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