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What percentage of the area under the normal curve is to the right of the following -score? Round your answer to two decimal places. z = 2.36

What Percentage Of The Area Under The Normal Curve Is To The Right Of The Following Score Round Your Answer To Two Decimal Places Z 236 class=

Sagot :

Given:

[tex]z=2.36[/tex]

Required:

We need to find the normal curve area to the right of the z=2.36.

Explanation:

The given z-score value is 2.36.

From the p-table, we get

The area under the curve between the mean and 2.36 is 0.49086

Add 0.5 to 0.49086 to find the area right of 2.36.

[tex]0.49086+0.5=0.99086[/tex]

Multiply by 100 to find the percentage of the area.

[tex]0.99086\times100=99.086\text{ \%}[/tex][tex]0.99086\times100=99.09\text{ \%}[/tex]

Final answer:

The percentage of the area under the normal curve is to the right of z =2.36 is 99.09%.

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