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If a square root parent function is vertically stretched by a factor of 6, what isthe equation of the new function, G(x)?A. G(x) = 65B. G(x) =-6/C. G(x) = V6xO D. G(x) == VE=

If A Square Root Parent Function Is Vertically Stretched By A Factor Of 6 What Isthe Equation Of The New Function GxA Gx 65B Gx 6C Gx V6xO D Gx VE class=

Sagot :

Solution:

When a function f(x) is stretched vertically by a factor of an integer n, it implies that the new function g(x) is n times its old function.

Thus,

[tex]g(x)=n\times f(x)[/tex]

Given a square root function, we have

[tex]f(x)=\sqrt[]{x}[/tex]

When the function is stretched by a factor of 6, let the new function be represented as G(x). This implies that

[tex]\begin{gathered} G(x)=6\times f(x) \\ =6\times\sqrt[]{x} \\ \Rightarrow G(x)=6\sqrt[]{x} \end{gathered}[/tex]

Hence, the new function G(x) will be expressed as

[tex]G(x)=6\sqrt[]{x}[/tex]

The correct option is A.

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