Answered

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a .1 kg leaves the barrel of 5 kg gun with a speed of 400 m/s.  determine the recoil speed

Sagot :

ANSWER

80 m/s

EXPLANATION

Given:

• Bullet's mass: 1kg

,

• Gun's mass: 5kg

,

• Bullet's final speed: 400m/s

Unknown:

• Gun's final speed

In this motion, momentum is conserved. Both initial speeds are zero because we can assume that before firing the gun and bullet are at rest. Thus, the momentum equation is,

[tex]m_b\cdot v_b+m_g\cdot v_g=0[/tex]

Solving for vg,

[tex]v_g=\frac{-m_b\cdot v_b}{m_g_{}}[/tex]

It is negative because its direction is opposite to the direction of the bullet's speed,

[tex]v_g=\frac{-1kg\cdot400m/s}{5\operatorname{kg}}=-80m/s[/tex]

The recoil speed is 80m/s

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