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A line with a slope of -2 passes through the point (4,2). What is its equation in slope-intercept form?

Sagot :

The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept

Substituting with m = -2 and the point (4, 2), we get:

2 = (-2)*4 + b

2 = -8 + b

2 + 8 = b

10 = b

Then, the equation of the line is:

y = -2x + 10

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