Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
[tex]\begin{gathered} X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{sin(\frac{\pi}{2})+sin(\frac{\pi}{6})}{2} \\ \\ X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{1+\frac{1}{2}}{2} \\ \\ X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{\frac{3}{2}}{2} \\ \\ X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{3}{4} \\ \\ X(\frac{\pi}{3})(\frac{\sqrt{3}}{2})=\frac{3}{4} \\ \\ X(\frac{\pi}{3})=(\frac{3}{4})(\frac{2}{\sqrt{3}}) \\ \\ X(\frac{\pi}{3})=\frac{\sqrt{3}}{2} \\ \\ X=sin,\text{ because sin\lparen}\frac{\pi}{3}\text{\rparen=}\frac{\sqrt{3}}{2} \\ \\ Hence \\ \\ sin(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{s\imaginaryI n(\frac{\pi}{2})+s\imaginaryI n(\frac{\pi}{6})}{2} \end{gathered}[/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.