Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
[tex]\begin{gathered} X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{sin(\frac{\pi}{2})+sin(\frac{\pi}{6})}{2} \\ \\ X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{1+\frac{1}{2}}{2} \\ \\ X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{\frac{3}{2}}{2} \\ \\ X(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{3}{4} \\ \\ X(\frac{\pi}{3})(\frac{\sqrt{3}}{2})=\frac{3}{4} \\ \\ X(\frac{\pi}{3})=(\frac{3}{4})(\frac{2}{\sqrt{3}}) \\ \\ X(\frac{\pi}{3})=\frac{\sqrt{3}}{2} \\ \\ X=sin,\text{ because sin\lparen}\frac{\pi}{3}\text{\rparen=}\frac{\sqrt{3}}{2} \\ \\ Hence \\ \\ sin(\frac{\pi}{3})cos(\frac{\pi}{6})=\frac{s\imaginaryI n(\frac{\pi}{2})+s\imaginaryI n(\frac{\pi}{6})}{2} \end{gathered}[/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
