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(-3, -3), (1, -5)find the slope

Sagot :

For this you can use the slope formula:

[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \text{ Where m is the slope and} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are the respective coordinates of the points} \end{gathered}[/tex]

So, in this case, you have

[tex]\begin{gathered} (x_1,y_1)=(-3,-3) \\ (x_2,y_2)=(1,-5) \end{gathered}[/tex][tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-5-(-3)}{1-(-3)} \\ m=\frac{-5+3}{1+3} \\ m=\frac{-2}{4} \\ \text{ Simplifying} \\ m=\frac{-2\cdot1}{2\cdot2} \\ m=-\frac{1}{2} \end{gathered}[/tex]

Therefore, the slope of the line through the given points is

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